ABCD is a rhombus whose diagonals meet at O. Find the value of x.
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Since diagonals of a rhombus bisect each other at right angle .
∴ In △AOB , we have
∠OAB + ∠x + 90° = 180°
∠x = 180° - 90° - 35° [∵ ∠OAB = 35°]
= 55°
Also, ∠DAO = ∠BAO = 35°
∴ ∠y + ∠DAO + ∠BAO + ∠x = 180°
⇒ ∠y + 35° + 35° + 55° = 180°
⇒ ∠y = 180° - 125° = 55°
Hence the values of x and y are x = 55°, y = 55°.
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