Question

ABCD is a rhombus whose each side is 5cm.AC=6, find BD​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

BD= 8cm

Step-by-step explanation:

Each side of rhombus=5 cm

AC= 6cm

We know that diagonals of rhombus are bisect perpendicularly

In right triangle AOB

AB=5 cm

OA=$\frac{1}{2}AC=\frac{1}{2}(6)=3 cm$

$AB^2=OA^2+OB^2$

Using Pythagoras theorem  

$(hypotenuse)^2=(Base)^2+(perpendicular\;side)^2$

Substitute the values

$5^2=3^2+OB^2$

$25=9+OB^2$

$25-9=OB^2$

$OB^2=16$

$OB=\sqrt{16}=4 cm$

BD=2(OB)=2(4)=8 cm

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