ABCD is a rhombus with ab is equal to 17 cm and diagonal AC is equal to 16 cm find the length of BD
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AB = 17 cm
Ac = 16 cm
rhombus has equal sides
AB = BC = CD = AD = 17 cm
AC = BD = 16 cm
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Answer:
Let ABCD be the rhombus with side 17 cm and AC and BD be their diagonals intersect
at O.AO=OC=15 cm
IntherightangledtriangleAOB,[inarhombusthediagonalsbisectat90degrees]
AB^2=OA^2+OB^2
OB=AB2−OA2−−−−−−−−−−√=172−152−−−−−−−−√=(17+15)(17−15)−−−−−−−−−−−−−−−√=8
BD=2∗8=16cm
Area=12∗AC∗BD=12∗30∗16=240cm2
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