ABCD is a rhombus with ab is equal to 17 cm and diagonal AC is equal to 16 cm find the length of BD
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Answer:
BD= 24.04
Explanation:
Given :
ABCD is a rhombus
All sides measures 17cm
AC ( diagonal) = 16cm
In triangle BCD
By Pythagoras Theorem
BD^2 = DC^2 + BC^2
( Hypotenuse square = base
square + perpendicular square)
BD^2 = 17^2 + 17^2
BD ^2 = 289 + 289
BD^2 = 578
BD = √ 578
BD= 24.04
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