ABCD is a rhombus with ABC=500
. Determine ACD.
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Answered by
2
Answer:
Since ABCD is a rhombus
⇒ ABCD is a parallelogram
∴∠ADC = ∠ABC = 50°[opp angles of a parallelogram are equal]
∵ Adjacent sides of a rhombus are equal
∴ AD = AC
⇒ ∠DAC = ∠ACD [angles opposite to equal sides are equal
= x(say)
∴ In △ACD we have
∠DAC + ∠ACD + ∠ADC = 180° ⇒ x + x + 50°= 180°
⇒ 2x = 30° ⇒ x = 65°
∴ ∠ACD = 65° .
hope it's help you
Answered by
2
Step-by-step explanation:
Since ABCD is a rhombus
⇒ ABCD is a parallelogram
∴∠ADC = ∠ABC = 50°[opp angles of a parallelogram are equal]
∵ Adjacent sides of a rhombus are equal
∴ AD = AC
⇒ ∠DAC = ∠ACD [angles opposite to equal sides are equal
= x(say)
∴ In △ACD we have
∠DAC + ∠ACD + ∠ADC = 180° ⇒ x + x + 50°= 180°
⇒ 2x = 30° ⇒ x = 65°
∴ ∠ACD = 65° .
so, plz mark me as brainliest answer.
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