Question

ABCD is a rhombus with ABC=74



Determine ∟ ACD​

Answer 1

Answer:

ACD=180°-(74°+90°)

=16°

Answer 2

$\bf{\gray{\underbrace{\red{Given:-}}}}$

ABCD is a rhombus with ABC = 74°

$\bf{\gray{\underbrace{\red{To\:find:-}}}}$

Angle ACD = ?

$\bf{\gray{\underbrace{\red{Solution:-}}}}$

Consecutive angles of a rhombus are supplementary.

Angle BCD = 180° – angle ABC

= 180° – 74°

= 106°

Angle BCD = 106°

Diagonals of a rhombus bisect the interior angles.

Angle ACD = Angle BCD / 2

= 106°/ 2

= 53°

Therefore,angle ACD = 53°

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