Question

ABCD is a rhombus with angle A = (2x-10)0 and angle B = (20+3x)0

. What is the value of

‘x’ Also find the measure of all the angles of this rhombus.

please answer with steps as soon as possible and I will mark you the braniest​

Answer 1

In rhombus, Let the line AC and BD intersect at a point called O.

The angle made by this two line at the Center is 90 degree. ( Property of Rhombus)

∠AOB=∠AOD=∠COD=∠COB=90

∠CBD=∠BDA=y ( Alternate Angles)

∠DCA=∠CAB=x ( Alternate Angles)

∴∠DAO=62−x

In triangle AOD,

∠DAO+∠AOD+∠ODA=180

62 - x + 90 + y = 180

y - x = 180 - 90 - 62

y - x = 28

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