Question

ABCD is a rhombus with angle ABC=56^ . Determine angle CAD​

Answer 1

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Answer 2

$\angle BOA = {90}^{o} \: \: \: \: \: (vertically \: oppossite \: \angle)$

$\angle BOA \:=\:180-56-90 = {34}^{o} \: \: \: \: \: \: \: sum \: of \: angles \: in \: a \: triangle$

$\angle BCA \:=\: {56}^{o} \: \: \: \: isosceles \: \triangle$

$\angle BCA = 180-56-56\:=\: {68}^{o} \: \: \: \:sum \: of \: angles \: in \: a \: \triangle$

$\angle CAB\:=\angle BAC-\angle BAO$

$\angle CAB\:=\:68-34$

$\therefore \angle \: CAB\:=\: {34}^{o}$