Question

ABCD is a rhombus with angle ABC = 56°.Determine angle CAD

Answer 1

∠BOA = 90º (vertically opposite angle)

∠BA0 = 180 - 56 - 90 = 34º (Sum of angles in a triangle)

∠BCA = 56º (Isosceles triangle)

∠BAC = 180 - 56 - 56 = 68º (Sum of angles in a triangle)

∠CAB = ∠BAC - ∠BAO

∠CAB = 68 - 34 = 34º

Answer: ∠CAB = 34º

Answer 2

ans : angle ACD=62°

Consecutive angle of a rhombus are supplementary .

∠BCD=180°- ∠ABC

=180°-56°

=124°

∠BCD=126°

Diagonals of a rhombus bisect the interior angles

∠ACD=∠BCD÷2

=124°÷2

=62°

Therefore,∠ACD=62°