ABCD is a rhombus with angle ABC equal to 126°. Find measure of angle ACD.
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Answered by
30
Answer:
54/2
Step-by-step explanation:
As in rhombus Opp. sides are parallel so in rhombus abcd AB is parallel to CD so angle ABC + angle BCD =180
so,126+x=180
so, x=180-126
=54
as diagonals of rhombus bisect opp. angle so angle ACD=54/2
=27
Answered by
16
Given,
ABCD is a rhombus with ∠ABC = 126°.
To Find,
Measure of ∠ACD.
Solution,
We know that,
ABCD is a rhombus
∴ ∠ABC + ∠BCD = 180° ( Linear Pair)
⇒ ∠BCD = 180° – 126° = 54°
Since AC is the diagonal of rhombus ABCD,
∠ACD = (½) ∠BCD ( In a rhombus, a diagonal divides an angle into 2 equal angles)
⇒ ∠ACD = (½) × 54° = 27°
Hence, the measure of the angle ACD is 27°.
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