Question

ABCD is a rhombus with angle Dab 56 degree determine angle DBC.. please answer as soon as possible with steps i have to submit it who answers it correct with step by step explanation they will be marked in brainlist​

Answer 1

Answer:

Step-by-step explanation:

∠BOA = 90º (vertically opposite angle)

∠BA0 = 180 - 56 - 90 = 34º (Sum of angles in a triangle)

∠BCA = 56º (Isosceles triangle)

∠BAC = 180 - 56 - 56 = 68º (Sum of angles in a triangle)

∠CAB = ∠BAC - ∠BAO

∠CAB = 68 - 34 = 34º

Answer: ∠CAB = 34º

Answer 2

Answer:

angle BOA =90°(VOA)

angle BAO=180-56-90=34(sum of angles in a triangle)

angle BCA =56°(ISOSCELES TRAINGLE)

ANGLE BAC =180-56=68(SUM OF ANGLES IN A TRIANGLE)

ANGLE DBC =ANGLE BAC -ANGLE BAO

ANGLE DBC=68-34

=34 ANSWER