Question

ABCD is a rhombus with each side of length 10 cm and one diagonal of length 10 cm find the area of Rhombus​

Answer 1

there is a property in rhombus which is that the sum of squares of all the sides is equal to the sum of squares of its diagonals. so

4 ×10×10=10×10+x×x

where x is the length of the Other diagonal

solving for X gives us that x is equal to 10 √3. now for the area of Rhombus the formula is

1/2×d1×d2

where D1 andD2 are the diagonals of the Rhombus

show the area of the Rhombus is

1/2× 10×10√3=50√3cm^ 2

so the answer is 50√ 3 cm^2