ABCD is a rhombus with length AB = 3.5 cm and OD = 2 cm. What is the length of AD and AO if the diagonal AC is three times of OD?
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Answer:
OD = 2cm
AC = 6cm
Step-by-step explanation:
Given : AB = 3.5 cm
Therefore, AD = DC = BC = 3.5 cm, since the lengths of all the sides in a rhombus are equal.
Given : AC = 3× OD
Given : OD = 2cm
Therefore, AC = 3×2 = 6cm.
Since the two diagonals bisect each other,
AC = AO + OC
So, AO = AC ÷ 2 = 6 ÷ 2 = 3cm
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