Math, asked by kevin070, 6 months ago

abcd is a rhombus with length da=5cm ob = 3cm where o is the point of intersection of the diagonals what is the length of bc and oa if the diagonal db is three times oc ?​

Answers

Answered by XxItzAnvayaXx
2

Answer:

Here, ABCD is a parallelogram and AC and BD are diagonals of parallelogram intersect each other at O.

Here, ABCD is a parallelogram and AC and BD are diagonals of parallelogram intersect each other at O.OA=3cm and OD=2cm

Here, ABCD is a parallelogram and AC and BD are diagonals of parallelogram intersect each other at O.OA=3cm and OD=2cmWe know that, diagonals of a parallelogram bisect each other.

Here, ABCD is a parallelogram and AC and BD are diagonals of parallelogram intersect each other at O.OA=3cm and OD=2cmWe know that, diagonals of a parallelogram bisect each other.∴ AO=OC and BO=OD

Here, ABCD is a parallelogram and AC and BD are diagonals of parallelogram intersect each other at O.OA=3cm and OD=2cmWe know that, diagonals of a parallelogram bisect each other.∴ AO=OC and BO=OD⇒ AC=2×OA=2×3cm=6cm

Here, ABCD is a parallelogram and AC and BD are diagonals of parallelogram intersect each other at O.OA=3cm and OD=2cmWe know that, diagonals of a parallelogram bisect each other.∴ AO=OC and BO=OD⇒ AC=2×OA=2×3cm=6cm⇒ BD=2×OD=2×2cm=4cm

Here, ABCD is a parallelogram and AC and BD are diagonals of parallelogram intersect each other at O.OA=3cm and OD=2cmWe know that, diagonals of a parallelogram bisect each other.∴ AO=OC and BO=OD⇒ AC=2×OA=2×3cm=6cm⇒ BD=2×OD=2×2cm=4cm∴ The length of the diagonals AC and BD are 6cm and 4cm.

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