ABCD is a rhombus with one diagonal eual to 18cm and length of each side equal to15cm.find the length of the other diagonals and area of rhombus.
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Answered by
5
If X is side of rhombus then,
4x^2 = AC^2 + BD^2 where AC & BD are diagonals.
so,
4 x 15^2 = 18^2 + BD^2
4 x 225 = 324 + BD^2
BD^2 = 900 - 324
BD^2 = 576
BD = 24
AREA OF RHOMBUS = product of diagonals / 2
= (24 x 18)/2
= 432/2
= 216 centimeter square
4x^2 = AC^2 + BD^2 where AC & BD are diagonals.
so,
4 x 15^2 = 18^2 + BD^2
4 x 225 = 324 + BD^2
BD^2 = 900 - 324
BD^2 = 576
BD = 24
AREA OF RHOMBUS = product of diagonals / 2
= (24 x 18)/2
= 432/2
= 216 centimeter square
Answered by
1
Here Side of the Rhombus is 15 cm,
d2 = 15
d2 = 15
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