Abcd is a smooth horizontal fixed plane on which mass m1=0.1kg is moving in a circular path
Answers
The speed of mass m1 is v = 10 m/s
Explanation:
Correct statement:
ABCD is smooth horizontal fixed plane on which mass m1 =0.1 kg is moving in a circular path of radius 1 m. It is connected by an idea string which is passing through a smooth hole and connects mass m = 1/ √2 kg at the other end as shown. m 2 also moves in a horizontal circle of same radius of 1 m with a speed of 10 m/s. If g=10 m/s^ 2 , then the speed of m 1 is?
Solution:
Given data:
- m1 =0.1 kg
- rm1 =1 m
- m 2 = 1/√2 kg
- rm2 = 1m
- v = √10 m/s
Since string is mass less tension on string will be same.
T cosθ = mg = g / √2
T sinθ = m2v^2 / R = 10 / √2
T = √ (g /√2)^2 + (10 /√2)^2
T = √200 / 2
T = 10 N
10 = m1v^2 /R = .1 / 1 v^2
v^2 = 100
v = 10 m/s
thus the speed of mass m1 is v = 10 m/s
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