Question

ABCD is a square. AC is quarter of a circle. Find the area of the shaded region.(π=22/7)​

Answer 1

Answer:

⇒  Side of square =7cm

⇒  Area of square OABC=(side)2=(7)2=49cm2

⇒  Here, radius of sector r=7cm and θ=90o

⇒  Area of sector OAPC=360oθπr2

⇒  Area of sector OAPC=360o90o×722×(7)2

∴  Area of sector OAPC=4×722×49=38.5cm2

⇒  Area of shaded region = Area of square OABC - Area of sector OAPC

∴ Area of shaded region =49−38.5=10.5cm2

Answer 2

Step-by-step explanation:

Area of the square=7×7= 49cm2

Area of the quarter of a circle= (22/7)×7×7÷4=38.5cm2

Area of shaded region = 49-38.5= 10.5cm2