Question

ABCD is a square and AC is one of its diagonals. Prove that ΔABC   = ΔCDA.​

Answer 1

Answer:

If ABCD is a square , AC and BD are the diagonals of the square that divides the square into two equal parts. If they divide the square into two equal parts then It is clear that the triangles and their angles are same to each other.

In the attached file, we can see that ac are the diagonals so is we Divide the square into two triangles, the triangles will add to form a square that is why they are 100% equal.

MArk as brainliest please!

Answer 2

Answer:

Applying the SSS rule ;-

AB = CD

BC = DA

AC = AC

$\: \: \: \:$(COMMON SIDE)

SO AABC CONGRUENTS TO ACDA (SSS)