Question

ABCD is a square and BD is the diagonal. Find the measure of the angles of triangle ABD. ​

Answer 1

Answer:

hope it helps you... the answer is attached

Answer 2

Step-by-step

In △ABD and △BCD,

In △ABD and △BCD,AB=CD(Each sides of a square are equal)

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)∴△ABD≅△BCD(By SAS)

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)∴△ABD≅△BCD(By SAS)Therefore,

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)∴△ABD≅△BCD(By SAS)Therefore,ar(△ABD)=ar(△BCD)(Congruent triangles)

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)∴△ABD≅△BCD(By SAS)Therefore,ar(△ABD)=ar(△BCD)(Congruent triangles)Therefore,

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)∴△ABD≅△BCD(By SAS)Therefore,ar(△ABD)=ar(△BCD)(Congruent triangles)Therefore,Area of square =ar(△ABD)+ar(△BCD)

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)∴△ABD≅△BCD(By SAS)Therefore,ar(△ABD)=ar(△BCD)(Congruent triangles)Therefore,Area of square =ar(△ABD)+ar(△BCD)⇒2ar(△ABD)= Area of square

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)∴△ABD≅△BCD(By SAS)Therefore,ar(△ABD)=ar(△BCD)(Congruent triangles)Therefore,Area of square =ar(△ABD)+ar(△BCD)⇒2ar(△ABD)= Area of square⇒ar(△ABD)=

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)∴△ABD≅△BCD(By SAS)Therefore,ar(△ABD)=ar(△BCD)(Congruent triangles)Therefore,Area of square =ar(△ABD)+ar(△BCD)⇒2ar(△ABD)= Area of square⇒ar(△ABD)= 2

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)∴△ABD≅△BCD(By SAS)Therefore,ar(△ABD)=ar(△BCD)(Congruent triangles)Therefore,Area of square =ar(△ABD)+ar(△BCD)⇒2ar(△ABD)= Area of square⇒ar(△ABD)= 21

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)∴△ABD≅△BCD(By SAS)Therefore,ar(△ABD)=ar(△BCD)(Congruent triangles)Therefore,Area of square =ar(△ABD)+ar(△BCD)⇒2ar(△ABD)= Area of square⇒ar(△ABD)= 21

In △ABD and △BCD,AB=CD(Each sides of a square are equal)∠BAD=∠BCD(Each 90°)AD=BC(Each side of a square are equal)∴△ABD≅△BCD(By SAS)Therefore,ar(△ABD)=ar(△BCD)(Congruent triangles)Therefore,Area of square =ar(△ABD)+ar(△BCD)⇒2ar(△ABD)= Area of square⇒ar(△ABD)= 21 Area of square