ABCD is a square and BXY is a triangle formed by extending AB to Y and CB to X Such that BX = BY . Find the measures of angle X and angle Y. pls fast
It's urgent!!!!!
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Step-by-step explanation:
ABCD is given square.
so, it's all angles are 90°
so, angle ABC = 90°
Now angle ABC = angle XBY --- { vertically opposite angles}
In ∆ XYB, BX = BY,
So, it is an isosceles traingle
As BX = BY
angle X = angle Y -----{ opposite angles to equal sides}
Now, angle XBY + angle X + angle Y = 180° --- {angles sum property of a triangle}
So, 90° + angle X + angle Y = 180°
angle X + angle Y = 180° - 90°
angle X + angle Y = 90°
But, angle X = angle Y
thus , angle X = angle Y = 45°
I hope you understand it
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