,ABCD" is a square and "E" is a point inside it such that "DE=BE." Prove that AEC" is a straight line.
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we have ABCD a square ,
DE=BE that means E is mid point of diagonal BD
we know mid point of one diagonal of square is also the mid point of others diagonal of square
so E is mid point of AC
this AEC is a straight line ,hence proved
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As ABCD is a square & DE=BE So we can say that point E is in middle as
it is such that "DE=BE."
So point E is also in middle of AC
so we can prove that "AEC" is a straight line.
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