Question

ABCD is a square and on the side CD, an equilateral triangle DCE is constructed by taking the point E in the exterior of square ABCD. Prove that 1)AE = BE, 2)BAE = 15​

Answer 1

Answer:

Step-by-step explanation:

In triangle ADE and BCE ,

Eq. 1 :

angleADC = angle BCD = 90°

angle EDC = angle ECD as triangle ECD is an equilateral triangle.

so angle EDA = angle ECB

AD = BC ( same sides of a square )

DE = CE ( equal sides of an equilateral triangle)

angle EDA = angle ECB

By SAS both are congruent. .....

By CPCT , AE = BE .....

Answer 2

Answer:

Step-by-step explanation:

ii) part is not clear