Question

ABCD is a square and triangle ABC is an equilateral triangle prove that ap is equal to dp​

Answer 1

Answer:

• this may help u....................

Answer 2

Bro I will just tell you directly the steps to solve it

Answer:

1) As the ∆ PBC lies on the side of square ABCD therefore all the sides of square and the ∆ will be equal.c

2) Now ∆ BPA and ∆ PCD can be proved that they are isoceles

3) We can find the measure of angle PBA and angle PCD by adding one angle of square which will be 90° and one angle of equi. ∆ which will be 60° .

4) We can find the measure of angle BAP and angle CDP because we know that they are angles of isosceles ∆ .

5) Now subtract the value of angle BAP from the right angle of square which is angle BAD , we will get the value of angle PAD of ∆ PAD

6) In the same way we can find the value of angle PDA and by converse of isosceles ∆ theorem we can prove that AP = DP .

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