Question

ABCD is a square Diagonals ACB and BD
intersect at 0.AB=10.5cm a circle
o is constuuctedy much that its area
is one-fifth.........​

Answer 1

Answer:

$Solution:Given: ABCD is a square, AC and BD are the two diagonals which intersect each other at O. Also, given that the angle bisector of ∠BAC meet BO at P and BC at Q.R.T.P: Proof:The diagonal BD bisects∠ABC and ∠ABC =90 because angle of a square.The diagonal AC bisects∠BAD and ∠BAD =90 because angle of a square.AQ bisects ∠BACIn ΔABP, ∠BAP = ∠BAQ =22.5 degrees ( Since A,P and Q lies on the same straight line)∠ABP=∠ABD=45 degrees (Since B, P and D lies on the same straight line)Sum$

Step-by-step explanation: