ABCD is a square E,F,G and H are the mid points of AB ,BC ,CD and DA respectivrly.such that AE = BF = CG =DH prove that EFGH is square
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ravinderamplpatgmu:
If all sides are equal then it is a rhombus not as
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Given AE=BF=CG=DH
⟹ So, EB=FC=GD=HA
In △s AEH and BFE,
AE=BF, AH=EB,
∠A=∠B (each ∠ = 90⁰)
∴ △AEH ≅ △BFE
⟹ EH=EF and ∠4= ∠2.
But ∠1 + ∠4 = 90⁰ ⟹ ∠1 + ∠2 = 90⁰
⟹ ∠HEF = 90⁰
And if ∠HEF = 90⁰ so, ∠EFG = 90⁰, ∠FGH = 90⁰ and ∠GHE = 90⁰.
Hence Proved.
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