Question

ABCD is a square. E is one fourth the way from A to B and F is one fourth the way from C. X is the centre of square. Side of square is 8 cm. Then find the area of the shaded region in cm sq

Answer 1

Answer:

Let the side of square be a

BF=2a and BE=3a (given)

⇒ Area of triangle FBE =21×FB×BE

⇒108=21×2a×3a

⇒a2=1296 cm

⇒a=36 cm

√a=362cm

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