abcd is a square, find out the value of x, y and z
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Answer:
In △ADB(AD=AB∵ABCD) is square
∠A=90
0
∵ABCD os square.
So,
∠ADB=∠ABD=45
0
(I have proved, although it is very basic thing which maight be remembered )
In △OEB
∠OEB+85
0
+45
0
=180
0
(Angle sum property for △S)
∠OEB=50
0
So,
x=180
0
−∠OEB=130
0
solution
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