Question

ABCD is a square. Find the values of a and b..
Please solve this i will mark u as brainlist. ​

Answer 1

We know that diagonal of a square divides the square into two equal triangle.

So here also diagonal AC divides the square into two equal triangles ADC and ABC in which,

angle DAC = angle BAC = 45°

angle DCA = angle BCA = 45°

angle ADC = angle ABC = 90°

Here in triangle ADE,

angle ADE + angle AED + angle DAE = 180°

a° + (180-82)° + angle DAC = 180°

a° + 98° + 45° = 180°

a° = (180-143)°

a° = 37°

Similarly in triangle ADF,

angle DAF + angle ADF = angle DFB ( as we know that summations of two interior angles is the exterior angle)

90° + a° = b°

90° + 37° = b°

b° = 127°

Hope it helps you.