ABCD is a square If angle PQR is equal to 90°PB=QC=DR prove that angle QPR =45°
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PBCR is a rectangle
PB=RC= z
⇒AP=z
If QC=RC=z
∴∠CRQ=∠RCQ= 45 degree
∠PRC= 90 degree
∴∠PRQ= 45 degree
sum of angles of a triangle = 180 degree
∴∠PQR= and ∠PRQ= 45 degree
∴∠QPR=180-(90 + 45)= 45 degree
PB=RC= z
⇒AP=z
If QC=RC=z
∴∠CRQ=∠RCQ= 45 degree
∠PRC= 90 degree
∴∠PRQ= 45 degree
sum of angles of a triangle = 180 degree
∴∠PQR= and ∠PRQ= 45 degree
∴∠QPR=180-(90 + 45)= 45 degree
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