ABCD is a square .If the measure of diagonals AC =52units, what is the length of a side?
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AC^2=CD^2+AD^2
Pythagoras theorem
(52)^2=X^2+X^2
2704=2X^2
X^2=2704/2
X^2=1352
X=√1352
X=36.8
the length of the sides= 36.8 units
Pythagoras theorem
(52)^2=X^2+X^2
2704=2X^2
X^2=2704/2
X^2=1352
X=√1352
X=36.8
the length of the sides= 36.8 units
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