Question

ABCD is a square in first quadrant whose side is a, taking AB and AD as axes, prove that the equationto the circle circumscribing the square is x + y = a(x + y).​

Answer 1

Answer:

Tell me if misread question

It is a circle of radius a/2 , whose centre is ( a/2 , a/2 )

Equation

$(x - \frac{a}{2} ) {}^{2} + {(y - \frac{a}{2}) }^{2} = (\frac{a}{2} ) {}^{2} \\ {x}^{2} + {y}^{2} + { {a}^{2} \over4} = a(x + y)$

Answer 2

Step-by-step explanation:

Hence, it is proved............