Math, asked by aaryansrao30, 7 months ago

ABCD is a square in which
AO = (7x+3) cm and OB = (6x+4)cm
where O is the
point of
a intersection
of the diagonals. What are the

length of the diagonals​

Answers

Answered by gs440150
0

Answer:

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Step-by-step explanation:

Answer:

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Explanation:

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Answered by mamtabgs395
2

Answer:

Here we have been given,

ABCD Is a trapezium in which CD parallel to AB andits diagonals intersect at 0.

A0=5x 7cm,0C=2x+1cm,DO= 7x-5cm and OB 7x+1cm. We know that the diagonals of a Trapezium Divide each other proportionally.

AO So, OT DO OB 2+1 7c+1 35x2- 49:x + 5x -7 14x2+7 10c- 5 21-41x - 2 =0 212- 42x+c -2 = 0 21a(r -2)+1(r -2) = 0 (21r + 1)(x -2) =0 2 = 0 or21r+1 = 0 =2 ort = =is Rejected Therefore = 2.

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