ABCD is a square in which line segment CX cuts ab at x and the diagonal BD at O such that angle COD=80degree and angle oxa =x degree.find the value of x.
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∠COD= 80
∠BOX= 80
as they are vertically opposite angles
diagonal of bisectors are at angle bisectors
∠OBX= 45
exterior angle= ∠OXA
exterior angle = sum of interior angle
∠OXA= 80 + 45
= 125
∠BOX= 80
as they are vertically opposite angles
diagonal of bisectors are at angle bisectors
∠OBX= 45
exterior angle= ∠OXA
exterior angle = sum of interior angle
∠OXA= 80 + 45
= 125
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