Math, asked by guptha, 1 year ago

ABCD is a square its side is 14 cm then find the shaded part of the figure

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guptha: pls answer fast

Answers

Answered by 15121115anil
4
area = 2× 22/7× 7×7 + 2× 1/2×14×7
area= 406 cm^2

dgdgj: how..
dgdgj: u can do that..............
dgdgj: bhai rhne do..iitti padhaiii...humare soch se pare h...
guptha: y did u used that formula
dgdgj: nothing
dgdgj: sorry...but why u blocked me.
Answered by MitheshShankar
4
the area of shaded region is 

radius of the circle is 7

2(  \pi r ^{2} ) + 2  (\frac{ \sqrt{3} }{4})a ^{2}

= 2 (  \frac{22}{7} x 7(7)) + 1/2 ( 14 x 14 )

= 2 ( 22 (7)) + 7(14)

= 308 + 98

= 406  cm^{2}

MitheshShankar: brainliest please
dgdgj: how u know there is equilateral triangle
MitheshShankar: i don't know whether they are equilateral or not but the areas of all triangles formed in a square are equal right
MitheshShankar: so i combined both the triangles
MitheshShankar: which became a right angle triangle
MitheshShankar: okay ?
dgdgj: yup
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