Question

ABCD is a square. M is the mid point of AB and CM
figure Show that CP = CQ​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

IN TRIANGLE AMP AND BMQ

M is the mid point of AB so

AM = MB

angle PMA = angle BMQ ( VERTICALLY OPPOSITE ANGLE )

angle PAM = angle MBQ ( ALTERNATIVE INTERIOR ANGLE )

SO TRIANGLE AMP = TRIANGLE BMQ ( BY ANGLE SIDE ANGLE RULE )

AND BY C.P.C.T MP = MQ

(IN TRIANGLE CMP AND CMQ)

CM = CM ( COMMON )

MP = MQ ( PROVED ABOVE )

ANGLE CMQ = 90 DEGREE ( GIVEN )

SO,BY LINEAR PAIR =CMQ + CMP = 180

= CMP = 180 - 90

CMP = 90

SO,ANGLE CMP = ANGLE CMQ

SO, BY SIDE ANGLE SIDE TIME TRIANGLE CMP = CMS

SO,BY C.P.C.T

CP = CQ

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