abcd is a square m is the midpoint of ab and pq is perpendicular to cm. prove that cp = cq
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Step-by-step explanation:
in triangle CMQ and triangle CMP
QM=PM. (given)
angleQMC=anglePMC(90°)
CM=CM (common)
triangle CMQ is congruent to triangle CMP
by sas criteria
so,CQ=CP(by cpct)
hope you understand what i tried to say
thanx
bahot likhna padta h yrr
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Step-by-step explanation:
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