ABCD is a square of 30 m long in the figure. Find the sea
Fig. 22.43
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GIVEN :-
- Length of rectangle , AB = 10 cm.
- Breadth of rectangle , AD = 6 cm.
TO FIND :-
- The area of shaded Portion.
SOLUTION :-
★ Diameter of Circle = 6 cm.
★ Radius of Circle = 6/2 = 3 cm.
✹ Area of Circle = πr².
→ 22/7 × (3)²
→ 22/7 × 9
→ 198/7
→ 28.28 cm².
✹ Area of rectangle = Length × Breadth
→ 10 cm × 6 cm.
→ 60 cm².
✹ Area of shaded portion = area of rectangle - area of circle
→ 60 cm² - 28.28 cm²
→ 31.72 cm².
Hence required area of shaded portion is 31.72 cm².
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