Question

ABCD is a square of 49 cm drawn with the centre A of a circle the perimeter of the quadrant formed by ABD IS​

Answer 1

Answer:

Perimeter of the quadrant formed by ABD is $= 175 cm$

Step-by-step explanation:

ABCD is a square of 49 cm.

AB = AD = 49 cm

A circle is drawn with A as the center and ABD as a quadrant.  Meaning, AB = AD = 49 cm as the radius.

Now perimeter of the quadrant formed by ABD is:

AB + Arc BD + AD

$= [49 + \frac{1}{4} . (2 . \frac{22}{7} . 49) + 49] cm$

$= [49 + 77 + 49] cm$

$= 175 cm$