ABCD is a square of area 1sq m P and Q are the midpoints of AB and BC respectively. Find the area of the triangle DPQ
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the area of the square is 1 square m,side of the square be length 1, then Then to find the area of triangle DPQ, subtract triangles APD, PBQ, and CDQ from the square of area 1.
= 1 - (0.25 + 0.25 + 0.125)
= 1 -0.625
= 0.375 m²
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