Question

ABCD is a square of radius 7cm and DEBA and AECB are the two quadrants at same base. Find the area of triangle EAB​

Answer 1

Solution:-

Given,

Side of Square = 7cm

Then, Base of ∆AEB = 7cm

As, AB = EB = AE

∆ABE is an Equilateral Triangle

$\red{\bold{✯\;Area\;of\; Equilateral\; triangle\;=\;√3/4 a²}}$

where, a is the side of an equilateral triangle.

$→\;{\sf{\frac{\sqrt{3}}{4}×7×7}}$

$→\;{\sf{\frac{\sqrt{3}}{4}×49}}$

$\Large{\blue{\bold{21.21cm²}}}$

Hope It Helps You ✌️

Answer 2

Answer:

Area of equilateral triangle = √3

Where A is the side of an equilateral triangle.

= √3/4 × 7× 7

= √3/4 ×49

= 21.21 cm²

Hope it helps you.

Mark me as brainliest answer plz.