ABCD is a square of side 14 cm and AED and BEC are semicircular as shown in the figure. find the area of the shaded region.
Answers
Answered by
44
Area of the shaded = Area of square-Area of 2 semicircular
= a^2-2(pai×r^2)/2
=14×14-(22/7×7×7)
=(196-154)cm^2
=42cm^2
= a^2-2(pai×r^2)/2
=14×14-(22/7×7×7)
=(196-154)cm^2
=42cm^2
Answered by
6
Answer:
Area of the shaded = Area of square-Area of 2 semicircular
= a^2-(pai×r^2)/2
=14×14-(22/7×7×7)
=(196-154)cm^2
=42cm^2
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