ABCD is a square of side 14 cm. Find the area of triangle AOB
nirmalark25:
What is O here?
Area of square=a²
Centre of square
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Answered by
8
Answer:
49 sq cm
Step-by-step explanation:
If we assume O as to be the mid-point of the diagonals, then the triangle formed OAB must be 1/4th of the square ABCD.
Area of ABCD = 14×14 = 196 sq cm.
therefore, Area of AOB = 196/4 = 49sq cm
Answered by
1
Area of triangle =1/4 Area of Square
A of ∆ =========1/4× a^2
Aof ∆ ===========1/4× 14×14= 49 sqcm
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2nd Method
Area of AOB = Area of Isosceles ∆
a/4 ×√(4b^2 - a^2)
a=14 ( equal side) & b= 7√2 (base)
A of ∆ =========1/4× a^2
Aof ∆ ===========1/4× 14×14= 49 sqcm
____________________________________
2nd Method
Area of AOB = Area of Isosceles ∆
a/4 ×√(4b^2 - a^2)
a=14 ( equal side) & b= 7√2 (base)
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