Question

ABCD is a square of side 14 cm. From each corner of the
care a quadrant of a circle of radius 3-5 cm is cut and also a circle of
radius 4 cm is cut as shown in the figure. Find the area of the remaining
(shaded) portion of the square.​

Answer 1

Step-by-step explanation:

Given ABCD is a square of side 14 cm. From each corner of the care a quadrant of a circle of radius 3-5 cm is cut and also a circle of radius 4 cm is cut as shown in the figure. Find the area of the remaining  (shaded) portion of the square.

• Area of square = side^2
•                       = 14^2
•                       = 196 sq cm
• Area of remaining shaded part = area of square – area of middle circle – area of 4 quadrants
• Now for the middle part so area of middle circle radius = 4 cm
• So area of circle = π r^2
•                          = 22/7 x 4 x 4
•                          = 50.28 sq cm
• Area of quadrant of circle = πr^2 / 4
• Given radius of quadrant of circle = 3.5 cm
• So area of 4 quadrant = 4 x π r^2 / 4 = π r^2
•                                                        = 22/7 x 3.5 x 3.5
•                                                       = 38.5 sq cm
• Area of remaining shaded part = area of square – area of middle circle – area of 4 quadrants
• Area of remaining shaded part = 196 – 50.29 – 38.5
•                                                = 107.21 cm

Therefore area of the remaining shaded portion will be 107.21 sq cm

Reference link will be

https://brainly.in/question/15940812