abcd is a square of side 15 cm calculate its distance and displacement
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Distance = Peremitere of the square
4× Side
4×15
60cm
Displacement= Length of diagnol AC
(AC)²= AB² + AD² [by Pythagoras theorem]
(AC)²= 15²+15²
AC = √225 +225
AC=15√2 cm
Therefore displacement=15√2cm
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