Question

abcd is a square of side 20cm.pqrs are mid points of ab,bc,cd,ad.dp ,aq cr ,ds are joined .find the area of inner square​

Answer 1

Answer:

Let the side of the outer square ABCD be a cm

⇒ Side of square PQRS =

2

BD

=

2

2a

=

2

a

=PS

And the side of square EFGH

=

2

GE

=

2

PS

=

2

(

2

a

)

=

2

a

cm

∴ Area of square EFGH =

2

a

×

2

a

=

4

a

2

cm

2

Given

4

a

2

=25⇒a

2

=100⇒a=10

∴ Perimeter of ABCD = 4a = 40 cm

Perimeter of PQRS = 4

2

a

=20

2

cm and perimeter of EFGH = 20 cm

∴ The required perimeter =(60+20

2

)

Step-by-step explanation:

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