Question

ABCD is a square of side 24 cm. EF is parallel to
BC and AE = 15 cm. By how much does
(i) the perimeter of AEFD exceed the perimeter
of EBCF?
(ii) the area of AEFD exceed the area of EBCF?
​

Answer 1

Answer:

i) 12 cm

ii)144cm^2

Step-by-step explanation:

Just refer the above diagram...

i)

$P (AEFD) = 2×(24+15)</p><p> \\ = 2× 39</p><p> \\ = 78 cm</p><p>$

$P(EBFC) = 2×(24+9)</p><p> \\ = 2×33 \\ 66cm$

Then, according to question their difference will be equal to :

= 78-66 = 12 cm^2.

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ii)

$Ar (AEFD) = 24 \times 15 = 360cm {}^{2}$

$Ar(EBFC) = 24 \times 9 = 216cm {}^{2}$

Then, according to question their difference will be equal to :

= 360-216 = 144 cm^2.

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• Here, remember to apply the formulas of rectangle and not the square.

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Hope it helps....!

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