Question

ABCD is a square of side 2m charges of +5nc, -10nc and -5nc are placed at corners A, B and C respectively. calculate the resultant electric field at point D​

Answer 1

Answer:

(5kμ/4) (√2 - 1)   towards BD

Explanation:              E = kq/r²

E due to 5μC = k(5μ)/2²

E due to -10μC = k(-10μ)/(2√2)²

E due to -5μC = k(-5μ)/2²

E due to 5μC and - 5μC act at 90°, so their effective E is

  ⇒ √[ (5kμ/4)² + (-5kμ/4)² ]

  ⇒ (5√2kμ/4)

Now the effective E and E due to -10μC is in the same direction,

Net E = (5√2kμ/4) + (-10kμ/8)

           = (5kμ/4) (√2 - 1)   towards BD

Answer 2

Explanation:

solution :

• = 2.25 × 10

• = 22.5 n

• hope it helps you