ABCD is a square of side 4 cm. A point E is taken inside the square such triangle Ecd is equilateral. Then area of triangle AEB
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given:-
AB=4cm
BC=4cm
CD=4cm
DA=4cm
ECD is equilateral triangle
then, EC & DE =4 cm ( because CD =4 cm)
therefore ,we say that ,
in triangle AEB , AE=4 cm
EB=4 cm
AB=4 cm
Area of triangle AEB=✓3/2×4
=✓3/1×2
=✓3×2
=3
Therefore ,area of triangleAEB is 3
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