Question

ABCD is a square of side 42 cm diagonal as intersect each other at taking over as a Centre arc AB and CD are drawn find the area of whole figure​

Answer 1

Answer:

ABCD is a square lawn of side 58m. AED and BFC are two circular ends.

Now, diagonal of the lawn = √(58)2 + (58)2 = 58√2m

It is given that diagonal of square = Diameter of circle

∴The radius of a circle having a centre at the point of intersection of diagonal

It is given that square ABCD is inscribed by the circle with centre O.

∴Area of 4 segments = Area of circle – Area of square

= πr2 – (side)2

m2

= 961.14m2

Area of whole lawn = Area of circle – Area of two segments

=5286.28 – 961.14

= 4325.14 m2