Question

ABCD is a square of side 5 cm. At the four corners,
four circular areas each of radius 1 cm are drawn. A
circle of radius 2.5 cm with centre O is drawn inside the
square. What is the approximate area of the shaded portion?
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Answer 1

Answer:

Area of shaded portion = Area of square − Area of circle −4( Area of a quadrant of a circle)

$= (5 \times 5) - \pi( {2.5})^{2} - 4 \times \frac{1}{4} \times \pi \times {1}^{2} \\ \\ = 2.235 \: {cm}^{2}$

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Answer 2

Area of shaded portion = Area of square − Area of circle − 4( Area of a quadrant of a circle)

= (5×5) − π(2.5)² - 4 × 1/4 × π × 1²

= 25 − 6.25π − π

= 25 − 7.25π

= 25 − ( 7.25 × 3.14 )

= 25 − 22.765

= 2.235cm²